pinv operation in matlab

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ANUSAYA SWAIN
ANUSAYA SWAIN el 20 de Abr. de 2024
Editada: Bruno Luong el 20 de Abr. de 2024
I have a matrix X of size [32X32X10]. I want to do pinv(X). But it suggested to use pagesvd(X). Now the dimension becomes [32X1X10]. However I want the matrix dimension to remain same that is [32X32X10].

Respuesta aceptada

Voss
Voss el 20 de Abr. de 2024
X = rand(32,32,10);
XI = pageinv(X);
size(XI)
ans = 1x3
32 32 10
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  3 comentarios
Steven Lord
Steven Lord el 20 de Abr. de 2024
From the pagepinv documentation page: "Introduced in R2024a"
Bruno Luong
Bruno Luong el 20 de Abr. de 2024
Thanks somehow I missed pagepinv when I looked up earlier.

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Bruno Luong
Bruno Luong el 20 de Abr. de 2024
Editada: Bruno Luong el 20 de Abr. de 2024
NOTE: This code is useful fonly or users who run version greater than R2021a and before R2024a, where pagesvd is supported by pagepinv is not..
A = pagemtimes(rand(4,2,5), rand(2,3,5)); % This should be your 32 x 32 x 10 matrix
piA = pagepinv(A)
piA =
piA(:,:,1) = -0.7143 -0.1994 0.8830 0.5803 3.6830 0.8982 -3.7827 -2.1157 -3.5004 -0.9739 4.3082 2.8220 piA(:,:,2) = 1.7339 -1.6101 0.2768 0.1140 -0.5683 0.8934 0.0456 0.2565 -1.1307 1.3152 -0.0816 0.1389 piA(:,:,3) = -0.7173 0.8751 0.5408 -0.0777 3.3456 -2.3089 -1.7138 0.8681 -1.6643 1.5736 1.0465 -0.3106 piA(:,:,4) = 11.6667 8.3580 -12.7967 -5.3279 -3.8216 -2.6054 4.4286 1.9206 -10.5258 -7.3566 11.8744 5.0506 piA(:,:,5) = -0.1933 0.0253 -0.3618 0.9475 -0.6336 -0.0070 -0.9652 2.2255 1.4941 0.2434 1.7190 -3.0276
% Check correctness
for k = 1:size(A,3)
norm(pinv(A(:,:,k))-piA(:,:,k),'fro')
end
ans = 0
ans = 0
ans = 0
ans = 0
ans = 0
function piA = pagepinv(A, tol)
sizeA = size(A);
m = sizeA(1);
n = sizeA(2);
if min(m,n) == 0
piA = zeros([n,m,sizeA(3:end)], 'like', A));
return
end
A = reshape(A,m,n,[]);
p = size(A,3);
[U,s,V]=pagesvd(A,'econ','vector');
if nargin >= 2
% user providestol, scalae or vector of length p
tol = reshape(tol, 1, 1, []);
else
smax = s(1,:,:); % ,porms of matrices
tol = max(m,n)*eps(smax);
end
s(s <= tol) = Inf;
S = reshape(s,1,size(V,2),p);
piA = pagemtimes(V./S,'none',U,'ctranspose');
piA = reshape(piA,[n,m,sizeA(3:end)]);
end
  2 comentarios
Paul
Paul el 20 de Abr. de 2024
Is this better than looping over the pages and calling pinv on each?
Bruno Luong
Bruno Luong el 20 de Abr. de 2024
Editada: Bruno Luong el 20 de Abr. de 2024
It's vectorized and potentially multithreaded via pagesvd, better I don't know. But it could be a stock function.

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