How to find norm of a 3 X 1 matrix if it contains components in parametric form?

%i have this coupler matrix in parametric form

syms t

coupler_parametric=[5163136522924301/2251799813685248, 2^(1/2)/2 - (8*t)/(t^2 + 1), - (4*(t^2 - 1))/(t^2 + 1) - 2];

i want to find magnitude of this matrix in terms of t

please someone help

[John D'Errico]

@Aman Please stop posting duplicate questions.

Answer 1

[Matt J]

syms t
coupler_parametric=[5163136522924301/2251799813685248,...
    2^(1/2)/2 - (8*t)/(t^2 + 1), - (4*(t^2 - 1))/(t^2 + 1) - 2];

norm(coupler_parametric)

ans = 

[Aman]

Sir,very much thank you for your answer.

But i think that there is mistake in calculating square of this term and adding 5163136522924301/2251799813685248.

If i am wrong,please correct me

[Torsten]

The norm of a vector x=(x1,x2,...,xn) is sqrt(x1^2+x2^2+...+xn^2).

x3 = sym('5163136522924301/2251799813685248');
x3^2

ans = 

[Matt J]

But i think that there is mistake in calculating square of this term and adding 5163136522924301/2251799813685248.

What is your basis for distrusting the calculation?

[Aman]

see 5163136522924301/2251799813685248 this number is greater than 1 ,so its square should be greater than 1 which i thought by seeing the output square which seems less than 1,which i misunderstood.

Thanks for your answer!!