Duplicate instances of methods executed while using parfeval and backgroundpool
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Harish Ananthakrishnan
el 20 de Jun. de 2024
Editada: Harish Ananthakrishnan
el 20 de Jun. de 2024
I have the following function that sends regular updates
function countUp(q)
%countUp Counts up 1 every second
for i = 1:5
disp(i);
pause(1);
send(q, i);
end
end
The above function is called by the mlapp
properties (Access = private)
q = parallel.pool.DataQueue; % Description
L;
f;
end
methods (Access = private)
function myDisp(app, data)
log = ['Recvd data update: ', num2str(data)];
disp(log);
app.Label.Text = num2str(data);
if(data == 5)
cancel(app.f);
app.StartButton.Enable = true;
end
end
end
% Callbacks that handle component events
methods (Access = private)
% Button pushed function: StartButton
function StartButtonPushed(app, event)
disp('Start button clicked');
app.StartButton.Enable = false;
app.L = afterEach(app.q, @(data) myDisp(app, data));
app.f = parfeval(backgroundPool,@countUp,0,app.q);
disp('Start button cb complete');
end
% Button pushed function: StopButton
function StopButtonPushed(app, event)
delete(app.L);
cancel(app.f);
app.StartButton.Enable = true;
end
First run returns
Start button clicked
Start button cb complete
Recvd data update: 1
Recvd data update: 2
Recvd data update: 3
Recvd data update: 4
Recvd data update: 5
Each time I start it it looks like duplicate instances of the function is executed
Start button clicked
Start button cb complete
Recvd data update: 1
Recvd data update: 1
Recvd data update: 2
Recvd data update: 2
Recvd data update: 3
Recvd data update: 3
Recvd data update: 4
Recvd data update: 4
Recvd data update: 5
Recvd data update: 5
It never looks like cancel(Future) is working as intended. What am I doing wrong?
1 comentario
Walter Roberson
el 20 de Jun. de 2024
For debugging purposes, I would do something like add a random number to the output. That would allow you to distinguish the case of the code executing twice (two different random numbers appear) from the case where the output is (for whatever reason) being displayed twice (same random number will appear for the pair of outputs)
Respuesta aceptada
Jaynik
el 20 de Jun. de 2024
Hi Harish,
Before setting up a new listener with afterEach, ensure that any previous listeners are removed. This can be done by deleting app.L if it exists. You can edit the StartButtonPushed function as below:
function StartButtonPushed(app, event)
disp('Start button clicked');
app.StartButton.Enable = false;
% Delete existing listener before creating a new one
if ~isempty(app.L)
delete(app.L);
end
app.L = afterEach(app.q, @(data) myDisp(app, data));
app.f = parfeval(backgroundPool,@countUp,0,app.q);
disp('Start button cb complete');
end
Hope this helps!
1 comentario
Harish Ananthakrishnan
el 20 de Jun. de 2024
Editada: Harish Ananthakrishnan
el 20 de Jun. de 2024
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