My roots don't match example roots when solving routh criterion

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I can't seem to figure out how to output similar roots as my teacher's. I've written the same code as he did (modified to match my problem).
The left is what I've started to input and the right is the example he gave us. When I also run my teachers code I get similar outputs to the one on the left. How do I get me roots to match his roots? This is a Routh Stability Criterion Problem with an unknown variable

Respuesta aceptada

Torsten
Torsten el 25 de Sept. de 2024
Movida: Torsten el 25 de Sept. de 2024
syms K s
p = s^3+9*s^2+12*s+15+3*K;
solve(p,s,'MaxDegree',3)
var2 = vpa(ans);
var = subs(var2,K,-1)

Más respuestas (1)

Sam Chak
Sam Chak el 25 de Sept. de 2024
From Part (a), you should have obtained the stable range of K: . Part (b) instructs you to verify the stability result by substituting the midpoint value of the stable range, and you should expect that the real parts of all roots are negative.
a = -5; % lower bound of stable range
b = 31; % upper bound of stable range
Kmid= (a + b)/2 % mindpoint of that range
Kmid = 13
syms K s
p3 = s^3 + 9*s^2 + 12*s + 15 + 3*K
solve(p3, s, 'MaxDegree', 3)
sol = vpa(ans);
%% Test
var = subs(sol, K, a) % the real-valued root must be zero
var = subs(sol, K, b) % the real part of the complex-valued roots must be zero
var = subs(sol, K, Kmid) % the real parts of all roots must be negative

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