Sin(pi) or cos(pi/2) problem with Matlab

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Kamuran
Kamuran el 10 de Mayo de 2015
Respondida: Karan Gill el 30 de Jul. de 2015
Hi,
I know that not getting ZERO for sin(pi) or cos(pi/2) in Matlab is an ongoing problem. My problem is inputting functions like
f=x^7+cos(x)^4/sin(pi*x) this is an only example input. It can be different but when sin(pi*x) is not equal to zero I will get a really large value but not inf and there is a difference between really large value and inf. Is there way to avoid or automatically filter this error.
the function can be also like f=x^7+cos(x)^4/sin(x) and when/if x=pi I need the function to be inf.
Anybody has a solution for this problem.
Thanks

Respuestas (2)

James Tursa
James Tursa el 10 de Mayo de 2015
Editada: James Tursa el 10 de Mayo de 2015
Pre-test the value of x. E.g., for scalar x:
if( floor(x) == x )
f = inf;
else
f = x^7 + cos(x)^4 / sin(pi*x);
end
xp = x / pi;
if( floor(xp) == xp )
f = inf;
else
f=x^7+cos(x)^4/sin(x)
end
But are you really OK with this behavior, but in cases where x (or xp) is one bit off from being an integer value, f is not inf? Or do you really want f to be inf for some range of small deviations from multiples of pi?
  1 comentario
Kamuran
Kamuran el 10 de Mayo de 2015
I would like to within small deviations of multiples of pi. But my major problem I don't know what function user will input to the code. There might be no sin or cos in the function. So I can not prepare for a specific function. I believe the only way out of this is to identify the problem to the user.

Iniciar sesión para comentar.


Karan Gill
Karan Gill el 30 de Jul. de 2015
If you have the Symbolic Math Toolbox, you can use sym to represent pi symbolically and calculate f . Then, use double to convert the answer back into type double. Try:
>> x = 0;
f = double(x^7+cos(x)^4/sin(sym(pi)*x))
f =
Inf

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