Why do I get conj(L)

3 visualizaciones (últimos 30 días)
Ken
Ken el 1 de Mzo. de 2025
Comentada: Walter Roberson el 1 de Mzo. de 2025
When I multiply 2 4X4 matrices one numeric the other alpha numeric say with L1,L2,L3, L4 why do I get the answer with cconj(L1,L2,L3,L4)? Also why do I get answers in fractions not decimal?

Respuesta aceptada

Star Strider
Star Strider el 1 de Mzo. de 2025
The Symbolic Math Toolbox assumes all variables are complex, so it adds the conj to be complete. Specifying that the variables are real in the syms declaration prevents that.
To convert the fractions to decimal fractions, use the vpa function. To always get decimal fractions, use the appropriate options in sympref. .
  1 comentario
Walter Roberson
Walter Roberson el 1 de Mzo. de 2025
Symbolic Math toolbox does not ordinarily add conj() for matrix multiplication or element-by-element multiplication.

Iniciar sesión para comentar.

Más respuestas (1)

Walter Roberson
Walter Roberson el 1 de Mzo. de 2025
Editada: Walter Roberson el 1 de Mzo. de 2025
You probably used the ' operator on the symbolic vector. For example,
syms L [1 4]
A = [2 3; 4 5]/7
A = 2×2
0.2857 0.4286 0.5714 0.7143
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
B = [L1 L2; L3 L4]
B = 
C = A*B
C = 
C = A*B'
C = 
whereas you might have wanted
D = A*B.'
D = 
To get the answer in decimal, either use
vpa(D, 10)
ans = 
or else use
sympref('FloatingPointOutput', true)
ans = logical
0
D
D = 

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by