Conveter a string with space in a number

A have one vector returned by the function textscan which have spaces inside the numerical string.
E.g.:
' 0 0 , 2 3 '
' 1 2 , 1 5 '
First, a have to substitute the ',' by '.' (it's simple) but how I remove the spaces? Because using str2num in this vector is returned error.

2 comentarios

Stephen23
Stephen23 el 26 de Ag. de 2020
Editada: Stephen23 el 26 de Ag. de 2020
"A have one vector returned by the function textscan which have spaces inside the numerical string."
I am surprised that no one brought up the obvious solution, to fix the (likely) problem at its source by handling the file encoding properly. Then textscan would import the data correctly.
Image Analyst
Image Analyst el 26 de Ag. de 2020
Well, someone might have, but the original poster forgot to attach the original text file. That is a common omission. For some reason, many/most posters totally ignore the posting guidelines that they are shown when they post the question, one of which says to attach their data.

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 Respuesta aceptada

Image Analyst
Image Analyst el 20 de Jun. de 2015
It's pretty much the same except that you set it equal to [] instead of a decimal point:
str(str == ' ') = []; % Remove spaces

3 comentarios

Hildo
Hildo el 20 de Jun. de 2015
How I can use this in this data annex (it's a cell data)? I try cellfun(@(str)str(str~=' '),dataArray{1,2}) but not work.
cellfun(@(str)str(str~=' '), dataArray, 'Uniform', 0)
cellfun(@(str)str(2:2:end), dataArray, 'Uniform', 0)
in the case where the odd-numbered characters are the blanks.

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Más respuestas (1)

Azzi Abdelmalek
Azzi Abdelmalek el 20 de Jun. de 2015
Editada: Azzi Abdelmalek el 20 de Jun. de 2015
s={' 0 0 , 2 3 ';'1 2 , 1 5 '}
a=strrep(s,',','.')
b=strrep(a,' ','')
out=str2double(b)

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Más información sobre Characters and Strings en Centro de ayuda y File Exchange.

Preguntada:

el 20 de Jun. de 2015

Editada:

el 26 de Ag. de 2020

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