using Matlab to plot density contour for scatter plot

93 visualizaciones (últimos 30 días)
Keqiao Li
Keqiao Li el 30 de Jun. de 2015
Editada: Walter Roberson el 8 de Feb. de 2023
Hi guys, I'm trying to use Matlab to plot the density contour for the following scatter plot. The bins will be 1X1 box. Within my limited understanding the density contour should be indicated how many points fall into the bins(correct me if I'm wrong), but I still cannot find a way to do the density plot. Need some help to solve this problem. Thanks!

Respuesta aceptada

Mike Garrity
Mike Garrity el 30 de Jun. de 2015
Scatter doesn't do any binning. It's showing each individual data element.
Perhaps this approach does what you want?
x = randn(1,1000);
y = randn(1,1000);
n = hist3([x', y']);
pcolor(n)
  4 comentarios
Keqiao Li
Keqiao Li el 2 de Jul. de 2015
Thank you Mike, I got what I want. Thank you for your help.
Andrea Ackroyd
Andrea Ackroyd el 3 de Dic. de 2018
I am commenting on this old post because I am doing a very similar thing, but achieving some unexpected results.
I am making a histogram2 (tile view) of one dataset, which is time samples of two variables. On the same axes I plot a contour of a map which comes from different data (essentially a target map for the time based data which is in the histogram).
The unusual behaviour is that the colour scale of the hist2 appears to be affected by having the contour on the same axes.
If it is noteworthy, I am plotting the contour first, with a solid colour for all contour lines (not using colormap). Then I plot the histogram second.

Iniciar sesión para comentar.

Más respuestas (3)

Walter Roberson
Walter Roberson el 30 de Jun. de 2015
Assuming that your data starts at 0 and contains fractional values and is to be binned by 1 x 1, and that your coordinates are in X and Y,
xidx = 1 + floor(X(:));
maxxoff = max(xidx) - 1;
yidx = 1 + floor(Y(:));
maxyoff = max(yidx) - 1;
counts = accumarray([yidx, xidx], 1); %remember Y corresponds to rows
imagesc(counts, 'XData', 1/2+[0 maxxoff], 'YData', 1/2+[0 maxyoff]);
hold on
contour(1/2+(0:maxxoff), 1/2+(0:maxyoff), counts)
The 1/2 offsets have to do with referencing the centers of the boxes.

Elena De Angelis
Elena De Angelis el 14 de En. de 2016
Editada: Walter Roberson el 14 de En. de 2016
Hi, I'm trying to do the same but my result is not what I expect, could someone tell me please what i'm doing wrong?
x = dNBR_filt_CHANGE;
y = NBR_post_CHANGE;
scatter(x,y,'r.')
hold on
[n,c] = hist3([x, y]);
contour(c{1},c{2},n)
  3 comentarios
geopap
geopap el 12 de Mayo de 2016
Editada: geopap el 12 de Mayo de 2016
I have exactly the same issue and unfortunately this doesn't work. Any other possible solution?
Update: In my case, where x and y are 1-column vectors, the n variable should be n'
Hamdullah OZOGUL
Hamdullah OZOGUL el 1 de Feb. de 2018
Editada: Hamdullah OZOGUL el 1 de Feb. de 2018
You just have to transpose the n to have the correct order.
contour(c{1},c{2},n')

Iniciar sesión para comentar.


Jos? Manuel Amigo
Jos? Manuel Amigo el 11 de Nov. de 2017
Editada: Walter Roberson el 8 de Feb. de 2023
PCx = rand(2000,1); PCy = rand(2000,1);
bins = 50; Msize = 10;
[N C] = hist3([PCx,PCy],[bins bins]);
CX = C{1}; CY = C{2};
N2 = N; N2(N2 == 0) = []; Nunique = unique(N2);
colors = jet(length(Nunique));
for i = 1:length(PCx)
if isnan(PCx(i))
PCxnew(i,1) = NaN;
PCynew(i,1) = NaN;
J(i,1) = NaN;
else
whichoneX = find(min(abs(CX - PCx(i))) == abs(CX - PCx(i)));
PCxnew(i,1) = CX(whichoneX(1));
whichoneY = find(min(abs(CY - PCy(i))) == abs(CY - PCy(i)));
PCynew(i,1) = CY(whichoneY(1));
J(i,1) = sub2ind([bins,bins],whichoneX(1),whichoneY(1));
end
end
for i = 1:bins
for j = 1:bins
temp = sub2ind([bins,bins],i,j);
Jthese = find(J == temp);
if ~isempty(Jthese)
Ntemp = N(temp);
Nthis = find(Nunique == Ntemp);
plot(PCx(Jthese),PCy(Jthese),'.','color',colors(Nthis,:),'Markersize',Msize);
hold on;
end
end
end
hold off;

Categorías

Más información sobre Scatter Plots en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by