Delete a row of a cell containing a certain number

I have a large cell array (a part of it I attached). This cell array contains other cells. My problem occurs at rows with contents similar to sequence{28,1} where I have zeros or numbers close to zero in the second column. How can I delete all rows which contain a number less than 0.001 in the second column. The numbers in the second column are cells themselves and the letters in the first columns are cells of characters.

Answer 1

[Azzi Abdelmalek]

A=A(A(:,2)>=0.001)

[Eli Dim]

this does not work, i think it is because the numbers of the second column are cells themselves and not doubles. I tried to do something like this:

    for i = 1:size(dispatch_seq,1)
        curCell_dispatch = dispatch_seq{i};
        curCell_disp_seq_power =  cell2mat(vertcat(curCell_dispatch_seq(:,2)));
        indices1 = find(curCell_dispatch_seq_power(:,1)<=0.01);
        curCell_dispatch_seq_power(indices1,:) = [];
        dispatch_seq(i) = {curCell_dispatch_seq_power};

In this way I get rid of the rows I don't want but I have no idea how to append the corresponding first column to this ...

[Azzi Abdelmalek]

out=cellfun(@(x) x([x{:,2}]>=0.001,:),dispatch_seq ,'un',0)

[Eli Dim]

Thank you, this works perfectly, but can you explain to me what the syntax means?

[Azzi Abdelmalek]

Cellfun allows you to apply any function you want to each cell. It's like a for loop, where x represent each cell at each increment. Read the Documentation