How to find the day number of any year from a date?
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Md. Golam Mostafa
el 23 de Jul. de 2015
Editada: Sergey Kostrukov
el 12 de Feb. de 2022
I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
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Peter Perkins
el 23 de Jul. de 2015
If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
2012 1 2
2012 3 3
2013 3 3
>> d = datetime(x)
d =
02-Jan-2012
03-Mar-2012
03-Mar-2013
>> day(d,'dayofyear')
ans =
2
63
62
2 comentarios
Peter Perkins
el 24 de Jul. de 2015
Presumably, you are not "using R2014b or later". datetime did not exist prior to that.
Más respuestas (3)
Andrei Bobrov
el 24 de Jul. de 2015
x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;
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Sergey Kostrukov
el 12 de Feb. de 2022
Editada: Sergey Kostrukov
el 12 de Feb. de 2022
Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)
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