How to find the day number of any year from a date?
170 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Md. Golam Mostafa
el 23 de Jul. de 2015
Editada: Sergey Kostrukov
el 12 de Feb. de 2022
I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
2 comentarios
Respuesta aceptada
Peter Perkins
el 23 de Jul. de 2015
If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
2012 1 2
2012 3 3
2013 3 3
>> d = datetime(x)
d =
02-Jan-2012
03-Mar-2012
03-Mar-2013
>> day(d,'dayofyear')
ans =
2
63
62
2 comentarios
Peter Perkins
el 24 de Jul. de 2015
Presumably, you are not "using R2014b or later". datetime did not exist prior to that.
Más respuestas (3)
Andrei Bobrov
el 24 de Jul. de 2015
x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;
0 comentarios
Sergey Kostrukov
el 12 de Feb. de 2022
Editada: Sergey Kostrukov
el 12 de Feb. de 2022
Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)
0 comentarios
Ver también
Categorías
Más información sobre Dates and Time en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!