How to add zeros to 2 x vectors where there are no matches, to get the same length ?

 x=[1 2 3 4];
 y=[1 2 3 1];
 x1=[3 4 5 6 7 8];
 y1=[2 6 4 2 5 3];
 [x, y, x1, y1] = Tout_Ajuster(x, y, x1, y1)

I want to put zeros where there is no match in x axes to get the same length for (x and x1) so I write a small code (Tout_Ajuster.m) in the output, x1 misses (5 and 6) so y1 miss(4 and 2) What is missing in my function < Tout_Ajuster.m > ???

[Jon]

It would help if you gave us the expected outputs for x1 and y1. Otherwise it's not clear what you're trying to do.

[Joel Sande]

% This is the expected output

x = [1 2 3 4 0 0 0 0]

x1 = [0 0 3 4 5 6 7 8]

y = [1 2 3 1 0 0 0 0]

y1 = [0 0 2 6 4 2 5 3]

%% Jon is very close to the answer, %% this is an other example :

ax = [3 5 9];

ay = [1 5 6];

bx = [1 2 10 15];

by = [3 4 5 2];

from that I want :

ax = [0 0 3 5 9 0 0];

ay = [0 0 1 5 6 0 0];

bx = [1 2 0 0 0 10 15];

by = [3 4 0 0 0 5 2];

Answer 1

[Joel Sande]

In this example, Test_Ajuster.m is calling Tout_Ajuster.m

Answer 2

[Jon]

Your question seems ambiguous to me, but based off my interpretation, see if this code gives you the result you're looking for:

   % This assumes that none of the matching x values are 0
   N = max(numel(x),numel(x1));
   xout = zeros(1,N);
   yout = zeros(1,N);
   x1out = zeros(1,N);
   y1out = zeros(1,N);
   % Reinsert the known values of x and y
   xout(1:numel(x)) = x;
   yout(1:numel(y)) = y;
   % Values in x1 (and the correponding y1 positions) that do not appear in x are set to zero
   for i = 1:numel(x)
       matching = find(x(i) == x1);
       if isempty(matching) == 1
           continue
       else
           x1out(matching) = x1(matching);
           y1out(matching) = y1(matching);
       end
   end

Gives the following results:

xout =

     1     2     3     4     0     0

yout =

     1     2     3     1     0     0

x1out =

     3     4     0     0     0     0

y1out =

     2     6     0     0     0     0

[Joel Sande]

I even found a better way to do it and plot it.

See attached file

Answer 3

[Azzi Abdelmalek]

n=max(numel(x),numel(x1))
x=[x zeros(1,n)]
x1=[x1 zeros(1,n)]
y=[y zeros(1,n)]
y1=[y1 zeros(1,n)]

Answer 4

[Joel Sande]

%% It is working now. Thank

ax = [3 5 9];

ay = [1 5 6];

bx = [1 2 10 15];

by = [3 4 5 2];

>> [a, b, c, d] = Tout_Ajuster(ax,ay,bx,by)

a =

     0     0     3     5     9     0     0

b =

     0     0     1     5     6     0     0

c =

     1     2     0     0     0    10    15

d =

     3     4     0     0     0     5     2