Initializing Array of Structures/Objects

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Sven
Sven el 5 de Sept. de 2015
Comentada: mary el 17 de Nov. de 2022
I simply want to set each struct in a struct-array. I set structarray to [] as it is an object property in my case, where it is being initialized as emtpy array. My first approach looks like:
structarray = [];
for i=1:10
structarray(i) = struct('index', i);
end
I get the following error: 'The following error occurred converting from struct to double: Error using double Conversion to double from struct is not possible.'
I can use an if else check and set the first element by:
structarray = struct('index', i);
Is there any easy way to write this straightforward similar to my code above?

Respuesta aceptada

Geoff Hayes
Geoff Hayes el 5 de Sept. de 2015
Sven - why not use arrayfun to apply a function to each element in the array. In this case, your function would create a struct with a single field called index where its value is assigned its position/index within the array. The following should do what you require
myStructArray = arrayfun(@(x)struct('index',x),1:10)
Note how the first input to arrayfun is the function that creates the struct given an input parameter. The value of each parameter is determined from the second input to arrayfun - an array of indices from one to ten.
Try the above and see what happens!
  3 comentarios
Bruno Luong
Bruno Luong el 17 de Nov. de 2022
myStructArray = arrayfun(@(i1,i2)struct('index1',i1,'index2',i2),zeros(1,10),zeros(1,10))
myStructArray = 1×10 struct array with fields:
index1 index2
mary
mary el 17 de Nov. de 2022
I found the answer:
myStructArray = arrayfun( @(x)struct('index1',x,'index2',x),zeros(1,10) )

Iniciar sesión para comentar.

Más respuestas (1)

Walter Roberson
Walter Roberson el 6 de Sept. de 2015
structarray = struct('index', repmat({[]}, 1, 10));

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