how to find euclidean distance for an image
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I have 100 images and i have to find the euclidean distance for it,and i have to take a query image and find the euclidean distance and retrieve the image ,i have extracted an feature of an image and have stored it in .mat file,please help
5 comentarios
Naz
el 22 de Dic. de 2011
Amazing. You have such diverse questions. I wonder how you manage to work on so many different things at a time.
Joel
el 13 de Mzo. de 2013
Dear FIR, could you please send me the files to this project so I can have a better look and see if I might be able to help.
Thanks
Image Analyst
el 13 de Mzo. de 2013
Joel, did you notice that FIR posted this 15 months ago? I doubt he still needs your help on it. Besides, he accepted an answer already.
Min Min
el 17 de Oct. de 2020
Can I use this formula to the find histogram similarity value "1-norm(y1-y0)/norm(y0)" which is used in image steganography
Image Analyst
el 17 de Oct. de 2020
I have no idea.
Respuesta aceptada
Más respuestas (5)
Junaid
el 21 de Dic. de 2011
1 voto
Dear FIR,
Similar question was asked by one fellow. The solution you can see from following URL. I hope it might help you.
6 comentarios
FIR
el 21 de Dic. de 2011
Junaid
el 22 de Dic. de 2011
Dear FIR,
Sorry FIR I can't overview your code you sent to me. To compute the Euclidean distance between images or image features, your vector length or matrix should have same dimensions. Let say your first image has 1 x 460 vector then your query should be of same length. If that is the case then you can easily find Euclidean distance by the code I have written below. You just have to ensure that the dimensions are the same. I give you example of Histogram feature of image.
I = imread('myimage.jpg');
I = rgb2gray(I);
h = imhist(I); % this will have default bins 256
% now second image
J = imread('myimage1.jpg');
J = rgb2gray(J);
h1 = imhist(J); % this will have default bins 256
E_distance = sqrt(sum((h-h1).^2));
You can do it for 1000 images as well.
sandeep kumar kailasa
el 12 de Feb. de 2017
How to get it for 10 images
Image Analyst
el 12 de Feb. de 2017
Sandeep, two code snippets for processing a sequence of files are in the FAQ: http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F
suma g
el 8 de Feb. de 2018
sir, how to calculate the distance only for particular feature say left eye and right eye
Image Analyst
el 8 de Feb. de 2018
You'd use the sqrt() function for that (calculating distance), once you have their coordinates.
Junaid
el 21 de Dic. de 2011
Dear Fir,
You have Query image Q, you want to compute euclidean distance of Q with all images in database. Is that you want ? If yes then Let say query Image Q is grayscale image so you can present it as feature vector
Q = Q(:); % this is one [size(Q,1) x size(Q,2) by 1]
all the images in database should have same dimensions. Let say every image and query image should have same number of pixels.
Now you load your database
D = load('Database.mat');
we assume that each column is one image and your number of columns should be size of Database. or if you want to present each row as image then simply take the transpose.
Q= repmat(Q,1,size(D,2));
E_distance = sqrt(sum((Q-D).^2));
Now E_distance have euclidean distance of Q with all images in database D.
Do let me know if It solved your problem.
3 comentarios
Image Analyst
el 21 de Dic. de 2011
He said "I have extracted features of 100 images and stored in .matfile.i have to find euclidean distance for those" so he wants to compare feature vectors, not the images themselves. Anyway trying to compare images on a pixel by pixel basis is only useful for certain kinds of situations, like characterizing compression/decompression algorithms, not, say for retrieving all images from a huge database that have faces in them.
FIR
el 21 de Dic. de 2011
FIR
el 22 de Dic. de 2011
Sean de Wolski
el 20 de Dic. de 2011
doc bwdist
doc graydist
might be some places to start.
1 comentario
FIR
el 21 de Dic. de 2011
Image Analyst
el 21 de Dic. de 2011
0 votos
The Euclidean distance is another image. What do you mean "query image by Euclidean distance"? I don't even know what that means. Please explain.
6 comentarios
FIR
el 21 de Dic. de 2011
Image Analyst
el 21 de Dic. de 2011
That's not when you'd use bwdist(). You simply need to use the Pythagorean theorem on your feature vectors:
generalizedDistance = sqrt(mean((featureVector1 - featureVector2)^2));
Weight the various features (elements) if you want to or need to. This will compare the feature vectors of two images. Then compare the feature vector of your reference image to the feature vector of all other images (by calculating generalizedDistance ) to see which image has a feature vector closest to the feature vector of your reference image.
FIR
el 21 de Dic. de 2011
Image Analyst
el 21 de Dic. de 2011
I don't understand that. What is that? Is your feature vector actually a cell array where the first cell has a 487 element row vector, same for the second cell, the third cell has a 359 element row vector, etc. Do you have 100 cells in your cell array? Feature vectors virtually never have thousands of features in them like that. I think you've chosen the wrong features. What does each feature represent? They should be things like the mean, standard deviation (for each color), perhaps the area fraction of edges or of "skin" pixels, maybe the presence of certain shapes, etc. Here's a nice database comparison that gets color feature vectors and retrieves images with those colors you select in it:
http://labs.ideeinc.com/multicolr/
FIR
el 21 de Dic. de 2011
Image Analyst
el 21 de Dic. de 2011
I probably won't get to it. I'm leaving on 9 day vacation to Florida in a couple of hours.
shradha naik
el 8 de Feb. de 2017
0 votos
hi.. i needed some help regarding implementing quadtree decomposition and histogram based image retrieval i wanted to apply quadtree on an image and then on the segmented image histogram needs to be computed can u please help me out??
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