Expression of y as a function of x for trigonometric equation

Hello everyone,

How can I come up with a expression of y as a function of x for the following equation ?

arccos(1-2y)-2(1-2y)(y-y^2)^0.5-X = 0

Or If I have X values stored in a file, how can I find y value for those x? Thanks in advance. Tanjina

[Image Analyst]

MATLAB is case sensitive. Is your X the same as your x? What is the value of y and big X that you put in?

Answer 1

[Torsten]

f=@(y,x)acos(1-2*y)-2*(1-2*y)*(y-y^2)^0.5-x;
fun=@(y)f(y,x);
y0 = [0 1];
for k=1:numel(X)
  x=X(k);
  Y(k)=fzero(fun,y0);
end

where X is the array in which your x-values are stored.

Best wishes

Torsten.