- The use of break looks ok!
- "I got some suspicious answers". How come "suspicious" ?
Can I use if ..break...else inside the same loop?
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My apology if it seems very trivial to all, but I have looked into the answers and could not find one single example which used if..break...else in the same loop. In my code, I want the value of t, where any of the variables x(t) or y(t) or z(t).... equals M (some pre set value) for the first time and then discontinue the iteration; otherwise it will return 0. So my code snippet looks like:
for i = 1:T
...
...
if x(t) == M || y(t) == M || z(t) == M || a(t) == M || b(t) == M
target = t;
break
else
target = 0;
end
end
I got some suspicious answers, so I was thinking whether the problem is in the use of break or the random probabilities I used in my code. Thanks.
2 comentarios
per isakson
el 21 de Oct. de 2015
Editada: per isakson
el 21 de Oct. de 2015
Respuesta aceptada
Robert
el 21 de Oct. de 2015
Editada: Robert
el 22 de Oct. de 2015
Your code looks fine. However, you can simplify the structure by adding target = 0; before your loop and omitting the else statement.
You might also consider using find(X==M,1), replacing X with each of your variables and then using min to find the index of the first occurrence of M, equivalent to your iterator i when you hit the break statement.
In any case, your use of if...break...else is not incorrect.
4 comentarios
Guillaume
el 22 de Oct. de 2015
A possibly more efficient way of achieving the same result:
target = find(any([x;y;z;a;b] == M), 1); %assuming x,y,etc. are row vectors.
Less to type anyway.
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