Need to combine doubles with different sizes

5 visualizaciones (últimos 30 días)
jgillis16
jgillis16 el 19 de En. de 2016
Comentada: jgillis16 el 20 de En. de 2016
I need to combine a set of doubles into one double matrix. My problem is that they are all different sizes. How would I go about doing this?
  3 comentarios
Walter Roberson
Walter Roberson el 19 de En. de 2016
Are you trying to put each member into a row (or column) with them starting as different lengths, and you want to end up with a rectangular matrix that has NaN in each location where there was no value?
jgillis16
jgillis16 el 19 de En. de 2016
Walter, yes you're on the right track. I have several different doubles that I need to combine but they all have varying lengths. The problem I'm facing is that say I have an 'x' double. This 'x' double is associated with another set of 'y' double that is the same length as the 'x' double because they come from the same source of data. But, I have several sets of these pairs of 'x' and 'y' doubles, but they are all different lengths. How would I make these separate 'x' and 'y' doubles the same length as each other?

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 19 de En. de 2016
If packing by columns then
YourXArray(1:length(x), Column_Number) = x;
If the x is larger then the current maximum number of rows then the array will be automatically grown and padded with 0s. If you want a different pad value then you need to indicate to us what padding you want.
  3 comentarios
Walter Roberson
Walter Roberson el 20 de En. de 2016
Then perhaps you should be padding with something else like -inf or nan
Lx = length(this_x);
if Lx > size(YourXArray,1)
YourXArray( size(YourXArray,1)+1 : Lx, :) = PadValue;
end
YourXArray(1:Lx, ColumnNumber) = x;
jgillis16
jgillis16 el 20 de En. de 2016
what does 'this_x', and 'x' refer to? thanks!

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by