Info
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
MATLAB error 'index exceeds matrix dimensions'
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
hello all
i want to run this function but i got index exceeds, i checked my loops but i could not saw the error.
where vn=vs=1 and M=100 and th1=1000 and Dr1=D1=0
function D=distortion(vn,vs,M,th1,x,y,Dr1,D1);
for i=1:M;
for j=1:M;
if i~=j
d1(i,j)=sqrt(((y(j)-y(i))^2+(x(j)-x(i))^2));
Dr1=exp(-d1(i,j)/th1)+Dr1;
end
end
end
for i=1:M
ds1(i)=sqrt(((y(j)-0)^2+(x(j)-0)^2));% point source at 0 0
cor2=exp(-ds1(i)/th1);
D1=cor2+D1;
end
D=(vs^2)-((vs^4)/(M*((vs^2)+(vn^2))))*(2*(D1-1))+((vs^6)/((M^2)*((vs^2)+(vn^2)))*Dr1);
end
0 comentarios
Respuestas (1)
Image Analyst
el 4 de Feb. de 2016
This worked for me.
function test1
vn=1
vs=1 ;
M=100 ;
th1=1000;
Dr1=0;
D1=0
y = rand(1,M);
x = rand(1,M);
D=distortion(vn,vs,M,th1,x,y,Dr1,D1)
end
function D=distortion(vn,vs,M,th1,x,y,Dr1,D1)
for i=1:M;
for j=1:M;
if i~=j
d1(i,j)=sqrt(((y(j)-y(i))^2+(x(j)-x(i))^2));
Dr1=exp(-d1(i,j)/th1)+Dr1;
end
end
end
for i=1:M
ds1(i)=sqrt(((y(j)-0)^2+(x(j)-0)^2));% point source at 0 0
cor2=exp(-ds1(i)/th1);
D1=cor2+D1;
end
D=(vs^2)-((vs^4)/(M*((vs^2)+(vn^2))))*(2*(D1-1))+((vs^6)/((M^2)*((vs^2)+(vn^2)))*Dr1);
end
What did you pass in for X and Y?
16 comentarios
Walter Roberson
el 5 de Feb. de 2016
You see the importance of showing us the actual error instead of just saying that you get an error somewhere?
La pregunta está cerrada.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!