How to use randperm to create a vector with multiples of the same number?

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Let's say I want to create a shuffled 1x26 vector with the values 2-11 but the value 10 comes up 4 times. So the vector might look something like
A = 2 10 10 3 4 10 6 7 10 8 9 11 5 10 10 10 2 4 3 5 11 7 9 6 10 8
What line of code would do that? I have previously used a similar code
A_before = repmat(1:13 , [1 2]);
A = A_before(randperm(26))
and would like something similar to that but where the range is 2-11 and value 10 appears four times. (So one batch of 13 values will have four 10s, the whole batch of 26 values will have a total of eight 10s)
  2 comentarios
Jan
Jan el 22 de Feb. de 2016
Editada: Jan el 22 de Feb. de 2016
What does "not with consecutive numbers" mean? Please define exactly, what you want to achieve. The less the readers have to guess, the better.
lauuser1
lauuser1 el 22 de Feb. de 2016
Well I guess I technically am looking for consecutive numbers but what I'm trying to say is instead of the numbers 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 I want it to be 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 11

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Guillaume
Guillaume el 22 de Feb. de 2016
So, why not?
A_before = repmat([2:11, 10, 10, 10] , [1 2]);
A = A_before(randperm(26))

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