how to detect background color of image ?
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ElizabethR
el 22 de Abr. de 2016
i want to make function, so if the background color if black like image 1, it will change to white.
But, if the background color image is white like in image 2, so it doesn't change.
How to make it ?? thanks
1 comentario
MJ Thangaraj
el 23 de Abr. de 2016
The image is Binary so it's obviously going to have only White and BLACK values.Check whether the background in white and then Complement the image .
Respuesta aceptada
Image Analyst
el 23 de Abr. de 2016
If you can make the assumption that the majority of the pixels in the image are the background color, then
[rows, columns] = size(binaryImage);
numWhitePixels = sum(binaryImage);
numBlackPixels = rows * columns - numWhitePixels;
if numWhitePixels > numBlackPixels
% Background is white.
% Do nothing at all.
else
% Background is black.
% Make image all white, everywhere at every pixel.
binaryImage(:) = true;
end
5 comentarios
Image Analyst
el 24 de Abr. de 2016
OK, then this should do it
bw = ~bw; % Change black into white and white into black.
Más respuestas (2)
Walter Roberson
el 23 de Abr. de 2016
Foreground and background are matters of intent. For example, often binary images are white for the parts that contain the information of interest, but binary images might be representing text and text is often represented in black (corresponding to books, which use dark ink on a white page.) Chess diagrams often use both black and white for the pieces. It is therefore not possible to detect which color is the "foreground" and which color is the "background" by computer program alone.
Luis Rosety
el 12 de Mayo de 2022
This is a very old question but I am learning Matlab and I got the same problem and just in case anybody else has the same question, I contribute with my own solution.
I realized it was quite straightforward the answer.
Assuming the input image is IM:
if(size(find(IM),1) > size(find(~IM),1))
% IM is white background
else
% IM is black background
end
1 comentario
DGM
el 12 de Mayo de 2022
Editada: DGM
el 12 de Mayo de 2022
Or much faster:
nz = nnz(IM);
if nz > (numel(IM)-nz)
% IM is white background
else
% IM is black background
end
You might also be able to consider the dominant value around the image periphery as some indicator of "background". I agree with Walter that the general solution requires knowledge of content and intent.
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