Undefined function or variable 'a'.

My current problem refers to the below script and function.
clear;
for x=100:145
assfunct1(x);
fprintf('x: %d, a: %d, b: %d, c: %d\n', x, a, b, c);
end;
&
function [a,b,c] = assfunct1(x)
if x<0 || fix(x) ~=x;
disp('error, input is not a non negative integer')
return
end
for a=1:x
b=sqrt(5*a^3);
c=sqrt((a+b)^2);
end
[a,b,c]
end
>> Assignment1
ans =
1.0e+03 *
0.1000 2.2361 2.3361
Undefined function or variable 'a'.
Error in Assignment1 (line 4)
fprintf('x: %d, a: %d, b: %d, c: %d\n', x, a, b, c);
Been trying for hours to work where I have erred, ty for any help you can offer.

3 comentarios

Image Analyst
Image Analyst el 3 de Mayo de 2016
You forgot to give the code for assfunct3(). You only gave it for assfunct1().
And can we assume that the code starting with "clear" is in a separate m-file, and not below assfunct1() definition in the same file?
Scott
Scott el 4 de Mayo de 2016
yes that's a typo, the code is for assfunct1 in the script
I answered this a few days back and as John correctly pointed out you should do this:
clear;
for x=100:145
[a,b,c] = assfunct1(x);
fprintf('x: %d, a: %d, b: %d, c: %d\n', x, a, b, c);
end;

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 Respuesta aceptada

John BG
John BG el 3 de Mayo de 2016

0 votos

You have to collect the output of your custom function assfunct3() with a variable that then you have to feed in the fprintf.
Since you call assfunct3 but do not collect the result with anything, then fprintf does not really know what variable 'a' is because the 'a' you use in the header of the assfunct3 remains local to that function.
If you find this answer of any help solving your question,
please click on the thumbs-up vote link,
thanks in advance
John

Más respuestas (1)

Jan
Jan el 3 de Mayo de 2016
You have to catch the outputs of the function:
for x = 100:145
[a, b, c] = assfunct3(x);
fprintf('x: %d, a: %d, b: %d, c: %d\n', x, a, b, c);
end
Note that the values of b and c are overwritten in each iteration:
for a = 1:x
b = sqrt(5*a^3);
c = sqrt((a+b)^2);
end
[a,b,c]
What is your intention?

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