for loop for variables
21 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Nachiket Patki
el 9 de Mayo de 2016
I have written one code as follows,
for i=1:10
Ai=i;
fprintf('A is: %d \n',Ai)
end
what i want to achieve from here is, I want to store 1,2,3..10 in variables A1,A2,A3...A10. But the code i have created is giving me Ai as variable instead A1,A2...etc and storing Ai=10 at the end.(It has also created row vector A=[1:10])
Respuesta aceptada
Azzi Abdelmalek
el 9 de Mayo de 2016
Editada: Azzi Abdelmalek
el 9 de Mayo de 2016
It's not a good idea to create variables A1,A2, ..., An. The array A=1:10 contains all your data. Why to create 10 variables, when one variable is sufficient
1 comentario
Más respuestas (1)
Weird Rando
el 9 de Mayo de 2016
@Stephen: Haha I read the same thing somewhere online. But that didn't stop me :3
for i=1:10
eval(sprintf('A%i = i',i))
end
3 comentarios
Stephen23
el 9 de Mayo de 2016
Editada: Stephen23
el 12 de Sept. de 2023
@Scott: this is how it often goes:
- beginner: I have a great idea!
- experienced user: what?
- b. I will access my variables dynamically!
- e. Don't do that, it is inefficient, complex, buggy, and hard to debug. Here is why...
- b. No! I am really cunning, and I know more than every experienced user who is advising me to use better, more reliable methods! I even know better than TMW, who wrote a whole page about avoiding dynamic variable names.
- e. Here are some better ways to...
- b. I am so great, it works!!!
- e. sigh.
Three years later:
- slightly-more-experienced beginner: damn, I have to rewrite all of this awful, slow, buggy code that I wrote! And I have to unlearn all these bad habits!
Weird Rando
el 10 de Mayo de 2016
It been three years, and yeah that did happen. Can't even understand what I code.
Ver también
Categorías
Más información sobre Whos en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!