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How can I apply the attached vector coding equation to a matrix in matlab?

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I currently am using atan2d(y,x) but I am unsure whether that is accounting for the y(i+1)-y(i) and x(i+1)-x(i) nature of the equation. x and y are defined as the two matrices I am comparing (i.e. knee versus ankle joint angles during a gait cycle).

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Star Strider
Star Strider el 25 de Mayo de 2016
It won’t account for it unless you tell it to:
Theta_vc = atan2d(diff(theta1), diff(theta2));
NOTE This should work with your data.
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Kylie Davis
Kylie Davis el 27 de Mayo de 2016
To be more specific... X is the ankle angle over a gait cycle, and y is the knee angle over a gait cycle. The vector coding phase angle I want is equal to tan-1(y(i+1)-y(i),x(i+1)-x(i)) for each consecutive data point (which is 101 points because data was normalized to 100% gait cycle).
Star Strider
Star Strider el 27 de Mayo de 2016
My code:
Theta_vc = atan2d(diff(theta1), diff(theta2));
does exactly what the expression in your image does. See the documentation on the diff function for details.
If you just have vectors, they will work with my code whether they’re row or column vectors. I don’t understand your gait cycle coding (an area peripheral to my areas of expertise). I would use atan2 or atan2d because they reflect the correct quadrants.
If you want to convert the angles you get as Theta_vc to 0°-360° or 0-2*pi, use the appropriate one of these functions:
Angles360 = @(a) rem(360+a, 360); % For ‘atan2d’
Angles2pi = @(a) rem(2*pi+a, 2*pi); % For ‘atan2’

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James Tursa
James Tursa el 25 de Mayo de 2016
Editada: James Tursa el 25 de Mayo de 2016
atan2d(y,x) will not do any difference calculations such as y(i+1)-y(i) or x(i+1)-x(i) as part of the calculation. So you would need to do that calculation before using atan2d (e.g. using the diff function). Are x and y 1D vectors or 2D matrices?
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Kylie Davis
Kylie Davis el 26 de Mayo de 2016
I believe it is 2D matrices. I am new to Matlab and am sorry if I'm asking a basic question. I appreciate your feedback thank you!

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