How can i divide a circle into 12 parts? 6 sectors having 15 degrees and the rest 6 having 30 degrees?
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MoonPie1
el 10 de Jun. de 2016
Respondida: Image Analyst
el 10 de Jun. de 2016
How can i divide a circle into 12 parts? 6 sectors having 15 degrees and the rest 6 having 45 degrees? How do i mask each 30 degree sector?
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Azzi Abdelmalek
el 10 de Jun. de 2016
t=-pi:0.01:pi;
r=1;
x=cos(t);
y=sin(t);
plot(x,y)
axis square
hold on
t1=linspace(-pi/2,pi/2,7)
x1=cos(t1);
y1=sin(t1);
x2=zeros(size(x1))
y2=zeros(size(x1))
plot([x1;x2],[y1;y2])
t1=linspace(pi/2,3*pi/2,13)
x1=cos(t1);
y1=sin(t1);
x2=zeros(size(x1))
y2=zeros(size(x1))
plot([x1;x2],[y1;y2])
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Image Analyst
el 10 de Jun. de 2016
She wanted six 45 degree sectors. The confusing part comes in the next sentence where she then refers to 12 30 degree sectors after she just said that there were supposed to be sectors of only 15 and 45 degrees. That's why I asked for the image.
Más respuestas (1)
Image Analyst
el 10 de Jun. de 2016
So I guess the problem is not solved yet. So, you should look at the FAQ http://matlab.wikia.com/wiki/FAQ#How_do_I_create_an_arc.3F and then once you have the coordinates of the sector, use the poly2mask() function to make your mask. Not hard. Let me know if you have problems.
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