How can I find the sum of the perimeter of a matrix?

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Alexandra Huff
Alexandra Huff el 5 de Ag. de 2016
Respondida: Ibrahim Abouemira el 19 de Mayo de 2019
Hi, I am wondering if I had a matrix [1,2,3;1,2,3;1,2,3] how I could find the sum of the perimeter. Thanks an advance.

Respuesta aceptada

dpb
dpb el 5 de Ag. de 2016
One way amongst any number...
>> M=[1,2,3;1,2,3;1,2,3];
>> I=ones(size(M)); I(2:end-1,2:end-1)=0;
>> S=sum(reshape(M.*I,1,[]))
S =
16
>>

Más respuestas (3)

Stephen23
Stephen23 el 5 de Ag. de 2016
Editada: Stephen23 el 5 de Ag. de 2016
In one line is easy and very fast:
>> M = [1,2,3;1,2,3;1,2,3];
>> sum(sum([M([1,end],2:end-1),M(1:end,[1,end]).']))
ans = 16
  5 comentarios
dpb
dpb el 10 de Feb. de 2018
[ ... Ricardo Florez Answer moved to comment since was a follow-up question on earlier Answer syntax ... dpb]
Hi. Why is it necessary to write two "sum" in the code: sum(sum(M(...)? Please see below:
the sum(M(:))-sum(sum(M(2:end-1,2:end-1)))
Thank you.
dpb
dpb el 10 de Feb. de 2018
Editada: dpb el 11 de Feb. de 2018
Because sum(M(2:end-1,2:end-1)) is a row vector of the sums of the columns in the submatrix; to get the total have to then add those values. This is taken care of in the first sum by the use of the special syntax (:) that returns all elements of an array/matrix in a column so sum only needs to add the one column vector. There is no syntax in Matlab to apply the secondary indexing operation to the result of the first function call return; there've been many suggest the enhancement.

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Sanjay Zamindar
Sanjay Zamindar el 28 de Jun. de 2018
Editada: dpb el 28 de Jun. de 2018
function final_sum = peri_sum(A)
size_row = size(A,1)
size_col=size(A,2)
Sum_of_first_row = sum (A(1, [1:1:end])); %base
Sum_of_first_Colmn = sum(A([2:1:size_row],1))
%sum_col= sum(A([2:1:size_col], [1:size_col:size_col]));
Sum_of_last_column= sum(A([2:1:size_row],size_col))
sum_of_last_row = sum(A(size_row,[2:1:size_col-1]))
final_sum = sum_of_last_row+ Sum_of_last_column+Sum_of_first_Colmn+Sum_of_first_row
end

Ibrahim Abouemira
Ibrahim Abouemira el 19 de Mayo de 2019

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