How to convert a string to a 8 bit Ascii one row binary vector?
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Jack Day
el 17 de Ag. de 2016
Hello everyone. I have for example the string:"abcd" i want to convert it to "01100001011000100110001101100100" (see the apendded zeros). as a logical vector.
thanks!
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Azzi Abdelmalek
el 17 de Ag. de 2016
Editada: Azzi Abdelmalek
el 17 de Ag. de 2016
s='abcd'
p=dec2bin(double('abcd'),8)'
out=p(:)'
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Stephen23
el 17 de Ag. de 2016
Editada: Stephen23
el 17 de Ag. de 2016
@Jack Day: ╞ , ╨ are not in the ASCII character set. ASCII only uses seven bits.
Those characters are in the Unicode "Box Drawing" set, which starts at 0X2500 (9472 decimal). There is no way that these can fit into seven (or even eight) bits!
To convert into a logical vector with eight bits per character, as the question requires:
reshape(dec2bin(+'abcd',8)',1,[])=='1'
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