non linear optimization returns a "Too many output arguments."
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Amani mahdy
el 17 de Ag. de 2016
Comentada: Matt J
el 17 de Ag. de 2016
Hello all,
I am using the genetic algorithm to solve a MINL problem, I am calling the non-linear-constraints as:
nonlcon = @non_linear_constraint_all_ga;
I have around 60 constraints, so nonlcon supposes to be a vector of 60 elements..
the called function is as follows :
function c1=non_linear_constraint_all_ga(x)
[~ ,c1,~]=objective_finction_and_non_linear_contsrains_ga(x);
end
i am taking only the second output from the BIG function "objective_finction_and_non_linear_contsrains_ga"
function [y ,c1,ceq1]=objective_finction_and_non_linear_contsrains_ga(x)
for (j=1 :Ns+2:(2+Ns)*Nc)
for (i=0:Ns-1)
k=i+1;
c1(1,m) = x(1,j+2+i).*sqrt(w((i+k),1)-x(1,j));
m=m+1;
end
end
end
I keep getting the following error :
Too many output arguments.
Caused by:
Failure in initial user-supplied nonlinear constraint function evaluation.
Any idea ?
best regards,
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Respuesta aceptada
Matt J
el 17 de Ag. de 2016
Editada: Matt J
el 17 de Ag. de 2016
The nonlinear constraint function must be equipped to return 2 arguments if requested, one for inequality and one for equality constraints.
function [c1,ceq1]=non_linear_constraint_all_ga(x)
[~ ,c1,ceq1]=objective_finction_and_non_linear_contsrains_ga(x);
end
2 comentarios
Matt J
el 17 de Ag. de 2016
No, ga will always request both c1 and ceq1 as outputs. However, if it sees that ceq1 is empty, it will realize that you have no equality constraints.
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