Does conv() function use FFT inside ?
8 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I have a very basic question(As it may sound!). Does the conv() function uses FFT to perform convolution? For performing the convolution of a 3D array, if I use conv() or ifft(fft(a)*fft(b)), will it yield the same result?
0 comentarios
Respuesta aceptada
Adam
el 7 de Nov. de 2016
conv does not use fft, or at least not when I last checked, as I wrote my own convolution function to use the fft in place of it.
If you get the padding and all that right then within computational error the results of conv should be equal to those of doing an ifft on the product of two ffts.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Fourier Analysis and Filtering en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!