Koch Square Problem : A(I): index out of bounds; value 4 out of bound 3
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Can someone please fix my error?
0 comentarios
Respuestas (1)
Walter Roberson
el 14 de Nov. de 2016
You use newpointsx(4) and newpointsy(4) before you have assigned anything to those locations. Two lines further on you use the (5) indices too.
5 comentarios
Walter Roberson
el 14 de Nov. de 2016
Your code has
v=[newpointsx(4);newpointsy(4)]-[newpointsx(2);newpointsy(2)]
vprime = R*v
f=[newpointsx(5);newpointsy(5)]-[newpointsx(3);newpointsy(3)]
fprime = R*f
newpointsx(4) = vprime(1)+newpointsx(2) %Point D
newpointsy(4) = vprime(2)+newpointsy(2)
newpointsx(5) = fprime(1)+newpointsx(3) %Point F
newpointsy(5) = fprime(2)+newpointsy(3)
Notice that you use newpointsx(4) and newpointsy(4) in calculating v, but you do not assign any value to newpointsx(4) or newpointsy(4) until 5 lines later in the code.
You need to assign values to newpointsx(4), newpointsx(5), newpointsy(4), newpointsy(5) before you can use them in calculations.
KSSV
el 15 de Nov. de 2016
@ Walter Roberson, I apologize, I have not seen all this discussion and in hurry closed the question. I shall be careful next time.
Ver también
Categorías
Más información sobre Octave en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!