- In what way does the code fail?
- What is the expected behavior?
- What is the unit of the data in intervals.mat
Finding values of a response within range of a cue
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Krispy Scripts
el 1 de Dic. de 2016
Comentada: Krispy Scripts
el 1 de Dic. de 2016
I have a matrix of two columns. The first column is cue times, as in times an animal was cued to do something. The second column is times that the animal responded. If the animal correctly responded then the animal will respond within a range of .15 seconds of cue and less then 5 seconds from cue. If so this is a correct behavior and needs to go into one matrix, if not then this is an error behavior and needs to go in another matrix.
This is the code I have written, but I am not sure why exactly it is not working.
Here is my code:
data=intervals;
cue=data(:,1);
response=data(:,2);
for k=1:length(cue)
for i=1:length(response)
if cue(k)+.15 >= response(i) && cue(k)+5<= response(i)
correct(i)=response(i);
else
error(i)=response(i);
end
end
end
I attached an example matrix of intervals.
Any help would be greatly appreciated.
3 comentarios
James Tursa
el 1 de Dic. de 2016
Note: error() is the name of a MATLAB intrinsic function. You should choose another name for your variable.
Respuesta aceptada
bio lim
el 1 de Dic. de 2016
Editada: bio lim
el 1 de Dic. de 2016
Take a look at your data (which is the same as intervals).
data =
81.436 735.18
272.1 1442.1
515.3 1682.2
575.42 1961.6
734.96 2507.1
915.2 2681.8
1319.4 2682.1
1441 2777.7
1526.6 3499
1681.5 0
1961.4 0
2087 0
2372.6 0
2559.9 0
2681.7 0
2838.6 0
3049.3 0
3141 0
3322.4 0
3498.9 0
None of the data satisfies your criteria, i.e.,
if cue(k)+.15 >= response(i) && cue(k)+5<= response(i)
correct(i)=response(i);
Hence all of them would go to error.
Your program is working fine, it's that your data doesn't qualify as the correct behavior.
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