Array that contains a geometric series

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shir shalom
shir shalom el 19 de Dic. de 2016
Comentada: shir shalom el 20 de Dic. de 2016
Hi, Is there a short way to create an array in which the elements are making a geometric series?
like for example the following array:
x=[1 2 4 8 16 32 64]
Thanks, Shir

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Roger Stafford
Roger Stafford el 19 de Dic. de 2016
A general form for a geometric series is:
[a,a*r,a*r^2,a*r^3,...]
You can generate n of these by:
s = a*r.^(0:n-1);
  1 comentario
shir shalom
shir shalom el 20 de Dic. de 2016
Thank you! that's a great general solution.

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John D'Errico
John D'Errico el 19 de Dic. de 2016
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John D'Errico
John D'Errico el 19 de Dic. de 2016
You could have said that the first time. But what is wrong then with this?
2.^(-1:6)
It really won't work? I guess I need to learn this new math then.
Or, for a more general form, with some other start point:
0.1*2.^(0:6)
Could I have used a loop? Of course. But why? Learn to use Matlab.
shir shalom
shir shalom el 20 de Dic. de 2016
Yes, sorry of course it works. I guess I was too tired to think last night. Thanks alot!

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