is it possible to do something like this in the loop:

if true
   % load Time;
   Time_test_1 = Time;
   clear Time;
   %load Time again;  
   Time_test_2 = Time;
   clear Time; 
   %load time again;
   Time_test_3 = Time;
   clear Time;
end

[Stephen23]

It is possible, but it is a really really bad idea. It is a very bad habit to learn. Naming variables in a loop makes your code slow, buggy, hard to debug, and harder to understand. Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Learn to use indexing rather than make lots of separate variables. Then your life suddenly gets better :)

Answer 1

[the cyclist]

Yes, but it is better to use a cell array instead of that naming convention ...

if true
   % load Time;
   Time_test{1} = Time;
   clear Time;
   %load Time again;  
   Time_test{2} = Time;
   clear Time; 
   %load time again;
   Time_test{3} = Time;
   clear Time;
end

which can easily be looped over ...

for ii = 1:3
  % load Time
  Time_test{ii} = Time;
  clear Time
end

This forum has hundreds of posts about why that is a better way to code.

[John Chilleri]

Or at least a vector, but you should definitely listen to 'the cyclist' and begin to use matrices and cells rather than naming conventions! This will help you with many issues down the road.

[jenka]

my Time variable is already a cell array?

[Guillaume]

So? You can have cell arrays of cell arrays.

If the cell arrays all have the same number of rows or columns, you could also concatenate them.

Note that I would avoid using load without an output. Rather than:

load('somefile');  %pops the Time variable into existence.
Time_test{idx} = Time;

Use filecontent = load('somefile'); Time_test{idx} = filecontent.Time;

There's no danger of unknowingly overwriting existing variables with the second method.