Subscripted assignment dimension mismatch
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Fadzli
el 7 de Feb. de 2017
Comentada: Fadzli
el 8 de Feb. de 2017
Hi, this is my code;
[r]=length(matrice_polar);
[www]=29;
matrice_cartesian=zeros(r,www);
temperature=zeros(r,www);
clear www
for i=1:r
matrice_cartesian(i,2:25)=[matrice_polar(i,1:24)];
distance_x(i,1)=(x_new-matrice_cartesian(i,2))^2;
distance_y(i,1)=(y_new-matrice_cartesian(i,3))^2;
distance_z(i,1)=(z_new-matrice_cartesian(i,4))^2;
total_distance(i,1)=(distance_x(i,1)+distance_y(i,1)+distance_z(i,1))^(1/2);
temperature(i,1)=matrice_cartesian(i,10);
end
for i=1:r
Delta_x(i,1)=(x_new-matrice_cartesian(i,2));
Delta_y(i,1)=(y_new-matrice_cartesian(i,3));
Delta_z(i,1)=(z_new-matrice_cartesian(i,4));
Delta_temperature(i,1)=(temperature-matrice_cartesian(i,10));
end
I get the error "Subscripted assignment dimension mismatch" at the last line:
Delta_temperature(i,1)=(temperature-matrice_cartesian(i,10));
Anyone can help me, why it is happen?
0 comentarios
Respuesta aceptada
Roger Stafford
el 7 de Feb. de 2017
Editada: Roger Stafford
el 7 de Feb. de 2017
’temperature' is an array, not a scalar, and when the scalar 'matrice_cartesian(i,10)' is subtracted from it, it remains an array. However, you are trying to place it in a single element of 'Delta_temperature' and it doesn’t fit. You need to rethink what it is you are trying to accomplish.
Más respuestas (0)
Ver también
Categorías
Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!