I am trying to find out performace metrics of an binary image, but I'm getting this error message : Assignment has more non-singleton rhs dimensions than non-singleton subscripts inline no.36

Recall = 0; %# TP / (TP + FN)
Precision = 0; %# TP / (TP + FP)
Fscore = 0; %# 2*(Precision*Recall)/(Precision+Recall)
green = [0,255,0];%# for FN
blue  = [255,0,0]; 
red   = [0,0,255]; %# for FP
white = [255,255,255];% # for TP
black = [0,0,0]; %# for TN

TP = 0; %# True positive pixels
FP = 0;  %# False positive pixels
TN = 0; %# True negative pixels
FN = 0; %# False negative pixels
y_res = 240; % Y - Resolution of the Image
x_res = 320; % X - Resolution of the Image
img_res=im2uint8(zeros(x_res,y_res,3));
img_gt=imread('gnd0005.bmp');
fg=imread('im0005.png');
img_fg=(imresize(fg,[320 240 ]));

for i = 1: y_res
  for j = 1: x_res
    pixel_gt = img_gt(i,j);% # ground-truth
    pixel_fg = img_fg(i,j); %# binary image
    if(pixel_gt == 255 && pixel_fg == 255);
        TP = TP + 1;
        img_res(i,j) = white;
            elseif(pixel_gt == 0 && pixel_fg == 255);
        FP = FP + 1;
        img_res(i,j) = red;
            elseif(pixel_gt == 0 && pixel_fg == 0);
        TN = TN + 1;
        img_res(i,j) = black;
            elseif(pixel_gt == 255 && pixel_fg == 0);
        FN = FN + 1;
        img_res(i,j) = green;
    end
  end
end

Answer 1

[Walter Roberson]

 img_res(i,j,:) = black;

And similar changes to the other assignments

[Bibhu Prasad Das]

Thank you

Answer 2

[Image Analyst]

Two other problems with your code.

First is that there are no comments.

Second is that you reversed x and y. In the for loop you have it correct -- img_res(i, j) which is img_res(y, x). However when you preallocated it you used

img_res=im2uint8(zeros(x_res,y_res,3)); % x and y in reverse order.

instead of

img_res = zeros(y_res,x_res,3, 'uint8'); % x and y in proper order.

[Bibhu Prasad Das]

Thanks for the logical answer.