Problem with using isfield

Dear all,
I have one structure with 4 fields and I would like to use function isfield for other work.
I have this part of code:
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
and I have this error:
Error using isfield
Too many input arguments.
Error in Newmodel (line 115)
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
Can you please advise me, how to change this part of code for good function? Thank you for your answers.

1 comentario

Jan
Jan el 6 de Abr. de 2017
The shown code has no valid Matlab syntax. Therefore the readers cannot know its intention. Suggesting a wrong idea might be more confusing then useful for you.

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Respuestas (2)

Thorsten
Thorsten el 6 de Abr. de 2017
Editada: Thorsten el 6 de Abr. de 2017

0 votos

if isfield(shape,'leftLung')
tmp3 = shape.leftLung{1};
end
if isfield(shape, 'rightLung')
tmp4 = shape.rightLung{1};
end
if isfield(shape,'spine');
tmp2 = shape.spine{1};
end

1 comentario

Steven Lord
Steven Lord el 6 de Abr. de 2017
You're probably going to want to add else blocks to each of those if statements, to assign default values to tmp3, tmp4, and tmp2 if the shape struct doesn't contain fields by those names.

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Jan
Jan el 6 de Abr. de 2017

0 votos

If you have a structure with 4 fields, checking the existing of fields is not necessary. I guess:
if isfield(shape,'leftLung') && isfield(shape,'rightLung') && isfield(shape,'spine')
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
end

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Preguntada:

el 6 de Abr. de 2017

Respondida:

Jan
el 6 de Abr. de 2017

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