Tracy - one way is to use ismemeber (though this can be "slow"). For example, suppose your column array is constructed as
c = randi(15, 25, 1);
m = [10 15];
Since ismember(c,m) returns a logical array of ones (indicating a match in m) and zeros (indicating no match) then we can sum up all the ones to determine how many elements of c are in m.
Note that the above is only valid for integers.