Loading files with a particular string on its name
133 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Ramiro Rea
el 16 de Ag. de 2017
Comentada: mirza
el 3 de Nov. de 2019
Hi everyone,
I have a series of files named like this:
Result_2017_5_24_13_44_IC.mat
Result_2017_5_24_13_54_MID.mat
Result_2017_5_25_13_20_SVO.mat
Result_2017_5_28_16_50_IC.mat
Result_2017_5_28_16_58_MID.mat
Result_2017_5_28_17_02_SVO.mat
I would like to load the files that have SVO, MID, and IC on its name separately. Is there a way of doing this? Right now I had to change the names of the files to something more simple to process. However, I would like to know a way of working with the files in their original name. The code I have right now works with the modification I do to the name:
for i=1:subjects
files = [num2str(i) '_SVO.mat']; %name of the files to process
load(files);
...
end
Many thanks, Ramiro
0 comentarios
Respuesta aceptada
Image Analyst
el 16 de Ag. de 2017
% Specify the folder where the files live.
myFolder = pwd; % or 'C:\Users\yourUserName\Documents\My Pictures' or whatever...
% Check to make sure that folder actually exists. Warn user if it doesn't.
if ~isdir(myFolder)
errorMessage = sprintf('Error: The following folder does not exist:\n%s', myFolder);
uiwait(warndlg(errorMessage));
return;
end
% Get a list of all files in the folder with the desired file name pattern.
filePattern = fullfile(myFolder, 'Result*.mat'); % Change to whatever pattern you need.
theFiles = dir(filePattern);
for k = 1 : length(theFiles)
baseFileName = theFiles(k).name;
fullFileName = fullfile(myFolder, baseFileName);
fprintf(1, 'Now reading %s\n', fullFileName);
% Now do whatever you want with this file name,
% such as reading it in as an image array with imread()
thisStructure = load(fullFileName)
end
msgbox('Done');
Más respuestas (1)
mirza
el 2 de Nov. de 2019
Editada: Image Analyst
el 2 de Nov. de 2019
How do I select "Result_2017_5_24_13_44_IC.mat" file if the values in the title are the variables.
For example, if
year=2014;Month=5; Day=24; x=13; y=44; z=IC
and we have to execute like this,
load(Result_year_Month_Day_x_y_z.mat)
Kindly, update me in this regard.
2 comentarios
Image Analyst
el 2 de Nov. de 2019
year = 2014;
Month = 5;
Day = 24;
x = 13;
y = 44;
z = IC; % z is a character array, not a number.
% Example: " Result_2017_5_24_13_44_IC.mat"
baseFileName = sprintf('Result_%d_%d_%d_%d_%d_%s.mat', year, Month, Day, x, y, z)
fullFileName = fullfile(folder, baseFileName)
if ~isfolder(fullFileName)
message = sprintf('File not found:\n%s', fullFileName);
uiwait(warndlg(message));
return;
end
s = load(fullFileName)
Ver también
Categorías
Más información sobre Startup and Shutdown en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!