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Expanding a Matrix with Repmat/Reshape?

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Cou
Cou el 18 de Ag. de 2017
Respondida: Jan el 18 de Ag. de 2017
I have two vectors:
x = [3 6 7 10]
y = [2 2 2 4]
I am trying to create vector
z = [3 3 6 6 7 7 10 10 10 10]
So each element x(i) is repeated y(i) times. This is straight forward with a for loop, but I'm trying to avoid looping, if possible. The size and values of x and y may change as well (they are populated by variables).
Here's the loop version:
z= [];
for i = 1:numel(y)
z= [z, repmat(x(i), 1, y(i))];
end
Any help is appreciated.

Respuesta aceptada

James Tursa
James Tursa el 18 de Ag. de 2017
Editada: James Tursa el 18 de Ag. de 2017
E.g.,
z = cell2mat(cellfun(@(x,y)repmat(x,1,y),num2cell(x),num2cell(y),'Uni',false));
But this just hides the loops in the background.

Más respuestas (3)

Steven Lord
Steven Lord el 18 de Ag. de 2017
If you're using release R2015a or later, use repelem.
x = [3 6 7 10];
y = [2 2 2 4];
z = repelem(x, y)

Matt J
Matt J el 18 de Ag. de 2017
Editada: Matt J el 18 de Ag. de 2017
Here's a truly loop free method,
clear p
p(cumsum(y,'reverse'))=1;
z=x(cumsum(flip(p)))

Jan
Jan el 18 de Ag. de 2017
x = [3 6 7 10]
y = [2 2 2 4]
z = repelem(x, y);
Or if this is the bottleneck of your code, try FEX: RunLength:
Z = RunLength(x, y);

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