insert row into table

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amateurintraining
amateurintraining el 18 de Nov. de 2017
Comentada: amateurintraining el 20 de Nov. de 2017
Hi. I want to make a function. This function has the input a table and a new value. How do I insert the new value into the table such that it is in order. I'm sorry if that is confusing but for example: I have a table:
a b
0 20000
120 15000
160 17000
200 19000
And I want to insert a new row where a=90. How do I do this if the provided function is already in order?

Respuesta aceptada

Walter Roberson
Walter Roberson el 18 de Nov. de 2017
mask = YourTable.a < 90;
newa = [YourTable.a(mask); 90; YourTable.a(~mask)];
newb = [YourTable.b(mask); NewBValue; YourTable.b(~mask)];
YourTable{:,[1 2]} = [newa, newb];
  2 comentarios
amateurintraining
amateurintraining el 20 de Nov. de 2017
That worked swimmingly. Thank you. How could I code it if NewBValue should be the interpolation between the above value and below value? I'm sorry if it's not very clear but essentially:
NewBValue= 20000+[(15000-20000)/(120-0)]*(90-0)
I'm trying to use the function interp1 but I don't quite understand it.
Walter Roberson
Walter Roberson el 20 de Nov. de 2017
interp_at = 90;
mask = YourTable.a < interp_at;
a_before = YourTable.a(mask);
a_after = YourTable.a(~mask);
b_before = YourTable.b(mask);
b_after = YourTable.b(~mask);
NewBvalue = interp1([a_before(end), a_after(1)], [b_before(end), b_after(end)], interp_at);
new_a = [a_before; interp_at; a_after];
new_b = [b_before; NewBValue; b_after];
YourTable{:,[1 2]} = [new_a, new_b];
However, you would probably find it much easier to adopt a modification of the technique that Akira Agata showed:
interp_at = 90;
new_a = [YourTable.a; interp_at];
new_b = interp1( YourTable.a, YourTable.b, new_a );
YourTable{:,[1 2]} = sortrows( [new_a, new_b] );
You can specify multiple locations in interp_at, as long as you make it a column vector.

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Más respuestas (1)

Akira Agata
Akira Agata el 18 de Nov. de 2017
How about concatenate 2 tables, and then sort it? Here is an example:
% Initial table
T = table(...
[0;120;160;200],...
[20000;15000;17000;19000],...
'VariableNames',{'a','b'});
% Additional data
T1 = table(90,19000,...
'VariableNames',{'a','b'});
% Concatenate and sort
Tout = [T;T1];
Tout = sortrows(Tout,'a');
The output is:
>> Tout
Tout =
5×2 table
a b
___ _____
0 20000
90 19000
120 15000
160 17000
200 19000
  1 comentario
amateurintraining
amateurintraining el 20 de Nov. de 2017
Thank you very much for your answer.

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