Variable Integer delay block

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Maria
Maria el 29 de Nov. de 2017
Comentada: Birdman el 29 de Nov. de 2017
Hi, I am not so familiar with Simulink so I hope someone can help. I have a signal that is an impulse, and I want to delay it; in particular, I want that the delayed version appears after 5ns. So far so good. I am looking into the block called "variable Integer Delay". What I did is to input as the delay "d" my 5 ns. But nothing happens. If I put, for example, "10" as "d", I do see a delayed version of the signal, but I am not sure how "10" is related to what I see.. Can someone explain me how does this block work? Hope I explained myself. Best
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Birdman
Birdman el 29 de Nov. de 2017
dt?
Maria
Maria el 29 de Nov. de 2017
dt= 1e-12 (sorry forgot to mention it)

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Birdman
Birdman el 29 de Nov. de 2017
Working with variable step solver for this situation is not recommended because there are some parameters which are set as auto and since you are working with too little time steps, it will not give you the desired result. I changed the solver to fixed-step and set the step size as dt. Also, I defined a fixed length of delay which is 5000, so when it is multiplied by 1e-12(dt), the length of delay will be 5e-9. When I run the simulation, I saw the desired result.
  2 comentarios
Maria
Maria el 29 de Nov. de 2017
Thank you so much! I got now that I have to put the delay length in terms of dt, so (delay)/dt, but it would have taken for me a long time to understand how set-up the solver! So in general, when I work with small time steps, is it the fixed-step always the best option? Thanks
Birdman
Birdman el 29 de Nov. de 2017
More reliable option, let's say. Because you force solver to take that specific step.

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