How I use fprintf to acess a struct?

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Gilberto Santos
Gilberto Santos el 15 de Feb. de 2018
Comentada: Guillaume el 16 de Feb. de 2018
I have defined the struct written down.
SATS_Hour = struct('SATS_H0',[],'SATS_H1',[],'SATS_H2',[],'SATS_H3',[],...
'SATS_H4',[],'SATS_H5',[],'SATS_H6',[],'SATS_H7',[],...
'SATS_H8',[],'SATS_H9',[],'SATS_H10',[],'SATS_H11',[],...
'SATS_H12',[],'SATS_H13',[],'SATS_H14',[],'SATS_H15',[],...
'SATS_H16',[],'SATS_H17',[],'SATS_H18',[],'SATS_H19',[],...
'SATS_H20',[],'SATS_H21',[],'SATS_H22',[],'SATS_H23',[]);
I have to access a struct to write on each individual SATS_Hour.SATS_H0 for the first time of my loop, it contains 48 loops. The number after the letter H, of each variable, must change up to the last one 47.
How can I do this?
Using fprintf or other Matlab command?
Thanks for the help.
Gilberto Fernandes

Respuesta aceptada

Guillaume
Guillaume el 15 de Feb. de 2018
Editada: Guillaume el 15 de Feb. de 2018
Numbering variables or structure fields is a bad idea. Any time you start naming things sequentially you need to think of using an array instead. Here, for example you'd be better off using a cell array. I.e use:
SATS_Hour = cell(23, 1); %instead of a structure
for idx = 1:23
SATS_Hour{idx} = ...
end
Indexing is always easier than awkward name construction via sprintf. If you're hell bent on using a structure:
for idx = 1:23
SATS_Hour.(sprintf('SATS_H%d', idx)) = ...
end
As you see, it's more complicated, less readable, and probably slower.
  4 comentarios
Stephen23
Stephen23 el 15 de Feb. de 2018
Editada: Stephen23 el 15 de Feb. de 2018
"If you're hell bent on using a structure" use a non-scalar structure:
for k = 1:23
SATS_Hour(k).SATS_H = ...
end
Guillaume
Guillaume el 16 de Feb. de 2018
I don't see how a structure array with just one field is any better than a cell array. Seems to add a level of indirection for no reason.

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Más respuestas (2)

Gilberto Santos
Gilberto Santos el 15 de Feb. de 2018
Thanks a lot. I am running the main program when it finishes I will run the function with your code suggestion.
I will keep you informed ASAP.
Best Regards,
Gilberto Fernandes

Gilberto Santos
Gilberto Santos el 16 de Feb. de 2018
Thanks you All. It worked. I have accepted the advice of using a cell array.
Best Regards to All,
Gilberto Fernandes

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