Why there is a difference between the dct computed by the MATLAB dct function and one computed by dct matrix multiplication?
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Mohsin Shah
el 26 de Feb. de 2018
Comentada: Mohsin Shah
el 26 de Feb. de 2018

The result is different, though both methods give inverse transform correctly.
0 comentarios
Respuesta aceptada
David Goodmanson
el 26 de Feb. de 2018
Editada: David Goodmanson
el 26 de Feb. de 2018
Hi Mohsin,
x needs to be a column vector as you did, but you don't need to take the transpose of dctmtx:
x = 1:8
y1 = dct(x')
y2 = dctmtx(8)*x'
y1 - y2
x1 = idct(y1)
x2 = dctmtx(8)\y2
Same results, out and back.
Más respuestas (0)
Comunidades de usuarios
Más respuestas en Power Electronics Control
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!