How do i create a big line with 3 portions ?

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sachin narain
sachin narain el 17 de Abr. de 2018
Editada: dpb el 17 de Abr. de 2018
i want to plot a line with 3 portions : 1) 0-500 with a slope of 10
2) 500-800 with 0 slope
3) 800-1000 with a slope of 10
in Matlab.It should look something like the picture i have attached.I am new to matlab.Kindly help

Respuesta aceptada

dpb
dpb el 17 de Abr. de 2018
Editada: dpb el 17 de Abr. de 2018
hF=figure;                 % make new figure, save handle to it
X=[0;500;800;1000];        % given X values
Y=[0;0;0;0];               % need Y for 3d plot even if 0
Z=[0;10*500;10*500;10*500+200*10];  % Z based on description given of line
hL=plot3(X,Y,Z)            % make the 3D plot, save handle if want modify properties
hAx=gca;                   % get the handle for current axes to mung on 'em
xlabel('X'),ylabel('Y')    % obvious??
ylim([-10,10])             % shrink the y-axis
grid on                    % make grid show up for accent
rat=get(hAx,'DataAspectRatio');  % retrieve the axis ratio array
rat(1)=1;                  % shorten the x-ratio to shrink y/z sizes comparatively--arbitrary
set(hAx,'DataAspectRatio',rat) % reset to that ratio

The only tricky part is that of setting the plot aspect ratio to make it look long and skinny like the original; read up on how that works--do a search in the doc search for dataaspectratio and you'll find a section on 'Manipulating Axes Aspect Ratio' that 'splains all about it.

hAx.ZTtick=[0 10000];
hAx.FontSize=6;
y=[1 1 1]*0.95; hF.Color=y;

produces

from which to start...albeit the background shading doesn't seem to show here as it does on monitor for some reason(*)...salt to suit.

(*) Oh, all that gets saved is the axes, not the full figure in the jpeg...

ADDENDUM

Z=[0;10*500;10*500;10*500+200*10];  % Z based on description given of line

Clearly the above way to generate the Z values is only sensible when there are so few segments and the line definition/values are such as to make it trivial to write what each line segment end values are by inspection.

  1 comentario
sachin narain
sachin narain el 17 de Abr. de 2018
Pefect.Thank you for the answer.Can you explain what you have done here?

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