Extracting the year from a timestamp in a column

I have a set of 477 values in a column, each that are formatted 'yyyy-mm-dd HH:MM:SS' and am trying to extract only the year using a loop

for i=1:477
    [t] = datevec(data{i,8},'yyyy-mm-dd HH:MM:SS');
        't_years' = t.Year;
end

Answer 1

[Stephen23]

Your code confuses a date vector (which is a simple double matrix of size Nx6 or Nx3) with a datetime object (which has the property obj.Year). If you want to use that property then you will need to use a datetime object. If you want to use datvec, then you do not need a loop as it accepts a cell array of char vectors directly. So probably something like this will work (it depends on how the data is arranged in data):

mat = datevec(data(:,8),'yyyy-mm-dd HH:MM:SS');
year = mat(:,1);

[Glowworm8]

Thank you!

[Peter Perkins]

And if you want to stick with datetimes (which you probably do),

d = datetime(data{i,8},'yyyy-MM-dd HH:mm:ss');
y = d.Year