Alternative to while loops without using loop?
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Hi, are there any more efficient alternatives to while loops. eg
a = zeros(3,1,3);
b = ones(3,1,3);
while isequal(a,b) == 0
a(:,:,1) = [round(rand);round(rand);round(rand)];
a(:,:,2) = [round(rand);round(rand);round(rand)];
a(:,:,3) = [round(rand);round(rand);round(rand)];
b(:,:,1) = [round(rand);round(rand);round(rand)];
b(:,:,2) = [round(rand);round(rand);round(rand)];
b(:,:,3) = [round(rand);round(rand);round(rand)];
end
I
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Respuestas (2)
the cyclist
el 5 de Sept. de 2018
a = zeros(3,1,3);
b = ones(3,1,3);
while not(isequal(a,b))
a = round(rand(3,1,3));
b = round(rand(3,1,3));
end
4 comentarios
the cyclist
el 5 de Sept. de 2018
Separate non sequitur remark ... if you have the Statistics and Machine Learning Toolbox, you could use the binornd command instead of round(rand()) to generate zeros and ones. I'm not sure which would be more computationally efficient, but I think what you are doing would be clearer.
Steven Lord
el 5 de Sept. de 2018
Another alternative would be to use randi specifying [0 1] as the first input.
the cyclist
el 5 de Sept. de 2018
Editada: the cyclist
el 5 de Sept. de 2018
Here is a way to do this without a while loop. It uses the trick I mentioned in a comment, that there are a finite number (512) ways of filling a 3x1x3 array with zeros and ones, and therefore there are 512x511 = 261,632 ways of choosing a pair of distinct entries.
In the code, I ...
- create the full list
- pick a at random
- delete that choice from the list
- pick b at random
list = dec2bin(0:511) - '0';
a_idx = randi(512);
a = reshape(list(a_idx,:),3,1,3);
list(a_idx,:) = [];
b_idx = randi(511);
b = reshape(list(b_idx,:),3,1,3);
The very first line is itself a pretty slick trick for getting all the permutations.
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