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multidimensional array as an input of function

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POLLY
POLLY el 26 de Sept. de 2018
Comentada: Adam Danz el 26 de Sept. de 2018
Thanks for taking the time to read this. I am working with 5D matrices (in my code resultG, resultX, resultY). These matrices contain 500*500 matrices that are generated 10 times(ntrials) for each value of q and n.
My question is how should I define resultG with indices as my input for function ADMM? I have attached a part of my script.
resultX=zeros(length(n),length(q), ntrials, M, N);
resultY=zeros(length(n),length(q), ntrials, M, N);
for i=1:length(n)
for j=1:length(q)
gamma = 6/((q(j) - p)*n(i));
for k=1:1:ntrials
[X,Y,Q, iter] = ADMM(resultG(i,j,k),c, n(i), gamma,tau, opt_tol, verbose);
resultX(i,j,k, :, :)=X;
resultY(i,j,k, :, :)=Y;
  2 comentarios
Adam Danz
Adam Danz el 26 de Sept. de 2018
"My question is how should I define resultG with indices as my input for function ADMM"
I understand that resultG is a 5D array but I don't see where that array is created. To answer your question, we'll need to understand the size and shape you expect resultG to be when going into the ADMM() function.
Would the squeeze() function be what you're looking for?
POLLY
POLLY el 26 de Sept. de 2018
Editada: POLLY el 26 de Sept. de 2018
I create that array using the following script. G, X0, and Y0 are all MxN matrices.
resultX0 = zeros(length(n), length(q), ntrials, M, N);
resultY0 = zeros(length(n), length(q), ntrials, M, N);
resultG = zeros(length(n), length(q), ntrials, M, N);
for i=1:length(n)
for j=1:length(q)
for k=1:ntrials
[G,X0,Y0]=matrix_plantsubm(M,N,c,n(i),p,q(j));
resultX0(i,j,k,:,:)=X0;
resultY0(i,j,k,:,:)=Y0;
resultG(i,j,k,:,:)=G;
end
end
end

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Respuesta aceptada

Adam Danz
Adam Danz el 26 de Sept. de 2018
It's still a little unclear what size and shape you expect resultG(i,j,k) to be going into the ADMM() function but if you expect it to be a matrix, use squeeze().
[X,Y,Q, iter] = ADMM(squeeze(resultG(i,j,k,:,:)),c, n(i), gamma,tau, opt_tol, verbose)
  2 comentarios
POLLY
POLLY el 26 de Sept. de 2018
Thank you! That works!
Adam Danz
Adam Danz el 26 de Sept. de 2018
Glad I could help.

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