how to store values in second column of cell array

In the following program, I get the value 200 X 1 after reshaping function, I want to store ground truth a label like 1 1 1 1 1 for the first five images then second 2 2 2 2 2 up to 40 images e.g.

 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 .
 .
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40

 clc;
 clear all;

 faceData = cell(40,5); % or cell(5,40)
 for i=1:40
    cd(strcat('s',num2str(i)));
  for j=1:5

       v=imread(strcat(num2str(j),'.bmp'));       

      v1 = imresize(v,[40,40]);
      [x1,y1] = size(v1);

      v1=v1(:);                                                    % it make long vertical vector
     w = uint8(v1);
     faceData{i,j} = w;                                         
  end
    cd ..
 end
 faceData = reshape(faceData,[],1);

[madhan ravi]

size(yourcell) ?

[Balaji M. Sontakke]

now it is 200 X 1 but i want 200 X 2 in second column i require

 1
 1
 1
 1
 1
 2
 2
 2
 2
 2
 .  
 .
 40
 40
 40
 40
 40

[Kevin Chng]

 faceData = reshape(faceData,[],2);

2 columns ! Does it answer you?

[Balaji M. Sontakke]

yes sir, but in second column values are again 1600 X 1 are stored instead of that I want to store values like

 1
 1
 1
 1
 1
 2
 2
 2 
 2
 2
 .
 .
 .
 40
 40
 40
 40
 40
 First five images one then second five images two up to last 200  
 images 40

[Kevin Chng]

200/5 = 40, therefore,

 faceData = reshape(faceData,[],40);

[Balaji M. Sontakke]

no sir that will create 40 column, I just want my cell array like

 First column   second column
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     1
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 1600x1 uint8     2
 .
 .
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40
 1600x1 uint8     40

Answer 1

[Kevin Chng]

   for i=1:1:length(faceData)
       faceData{i,2}=ceil(i/5);
   end

Add the code above to the below of your code.

Kindly accept my answer if it is working for you.

[Balaji M. Sontakke]

Thanks sir