running x.m file many times. I want to store values separately.

I am running x.m file 25 times repeatedly in one go. I want to store separately max and min values(operations in x.m file) of each iteration in matrix form in mat file. Can anyone suggest?

[dpb]

More efficient to pass the 25 datasets as array, possibly, and return the array of results. Would need to know the input data form for specific code.

Alternatively, since is counted number, preallocate an array of N(=25),2 and store the results with a loop index. Of course, the function x has to return the values to the caller.

[N/A]

Thank you but can you elaborate it. As x.m file is calculating results from random values and it is giving results but I want to compare each result of each iteration,say for 25 times. so it will generate 25 max values but how to store the maximum maxvalue among each maxvalue separately. And how can I store values separately so that I show the results as .mat file. eg.

iteration=25;
g=10;
for ii=1:-1:iteration
  for ij=1:-1:g
    if MaxValue(ii,ij)>=MaxValue(ii,ij-1)
      MaxValue=MaxValue(ij);
    else
      MaxValue=MaxValue(ij-1);
    end
  end
end

[dpb]

iteration=25;
for ii=1:-1:iteration
  ...

won't do anything-- 1:-1:25 is a "do nothing" loop because after the first iteration the next iteration would be for i=0 and the colon operator won't create the vector at all when the iterator doesn't fit with the start and end values given.

[dpb]

Again, what need to know is what is the return from x function? Is it a 1x2 vector [min,max] or 25x2 or something else?

Is the max of this other iteration the max of a 25x2 array then, though, I presume? The simplest way presuming the result of call ing x is indeed the 1x2 array is probably to just save those in a new array and then call min/max on that array.

[N/A]

Thank you. Actually I am taking max(profits) and I want to store this value so that on next iteration I can compare both max values and want to store maximum among them. So basically for one iteration it is 1x1 array and finally as a result I want maximum max value among all iterations but also want to store max of each iteration. I am facing problem in comparison as in mat file i am having only max value of last iteration which is not sufficient. Thank you again.

[N/A]

this image is for iteration=2;but it is storing only max value of iteration=2. instead of that i want to store and compare both max values. so i want this for each iteration.

Answer 1

[dpb]

N=25;             % or whatever max number is
n=5;              % or whatever number observations/iteration is
p=zeros(N,n);     % holding array for the results of N iterations w/ n results/iteration
for i=1:N
  for j=1:n
    p(i,j)=x(....);  % each call to the function returns one profit value???
  end
end
[mxpgen,ixgen]=max(p,[],2);  % max of each generation by iteration and which generation
[mxptot,ixtot]=max(mxpgen);  % max overall and which iteration contained it

If you modify x to operate in vector sense, it could return the first result itself.

[N/A]

It can be helpful but here x.m is a file not a function and doing many computations so I am stuck here so please tell how to work with it.please suggest. thank you.

[dpb]

Make it a function...

[N/A]

I did some manipulation in previous suggestions then it worked. Thank you so much for help. you helped me very much.

[dpb]

Glad to hear it...I knew you could do it! :)

[N/A]

without your help it won't be possible. really thank you. :)