How to create an array that counts the number of consecutive repeating numbers in a given array?
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Susan Santiago
el 26 de Nov. de 2018
Comentada: Susan Santiago
el 3 de Dic. de 2018
For example, if I have a matrix something like this, A = [1;1;1;2;2;2;2;2;3;3;4;4;4;4;4;4;4;5;5;5;5;1;1;1;3;3;3;3;3;3]. How would I create a matrix that looked like this?
B = [1;2;3;1;2;3;4;5;1;2;1;2;3;4;5;6;7;1;2;3;4;1;2;3;1;2;3;4;5;6]. So it counts up to 3 since there are 3 ones. And then up to 5 since there are 5 2s. I was going to use the unique function for this but don't think it'll work because some of the numbers repeat nonconsecutively. Please help!
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