why nanmean error?
16 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Lilya
el 24 de Dic. de 2018
Comentada: madhan ravi
el 3 de En. de 2019
Hi all,
I am trying to average 3d matrix that have nan values, but I am getting the following error:
Error using nanmean
Too many input arguments.
and the resulted matrix when i used mean function it doesn't show any data
any suggestion?
Thanks u
1 comentario
Guillaume
el 24 de Dic. de 2018
any suggestion?
Clearly, you passed too many inputs to nanmean. Crucially you haven't shown us how you call nanmean so it's difficult to say exactly what you do wrong.
Note that since R2014b (I think), there is no need to use nanmean, the regular mean function can ignore nans.
Respuesta aceptada
Star Strider
el 24 de Dic. de 2018
Editada: Star Strider
el 24 de Dic. de 2018
You may have your own function or a variable that you named ‘nanmean’.
Run this from a script or your Command Window:
which nanmean -all
If the first result is:
nanmean is a variable.
You have found the problem. The solution is to re-name your function or variable to something that does not overshadow any MATLAB functions, and is meaningful to you.
6 comentarios
Star Strider
el 24 de Dic. de 2018
No worries, and no need to apologise. It is a relatively common belief that most of us are MathWorks employees (‘MathWorkers’). Only those with the blue ‘STAFF’ label by their names actually are. The rest of us are just here for the fun of it!
Más respuestas (1)
madhan ravi
el 24 de Dic. de 2018
Editada: madhan ravi
el 24 de Dic. de 2018
If your using 2018b version just use mean with 'omitnan' as a name pair
doc mean % if and only if your using 2018b to use them with n dimensions
2 comentarios
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!